Given the following, how do you calculate (a) the mass of water required to dissolve one hundred grams of sugar at 100°C and (b) the amount of sugar that remains in solution when the mixture in (a) is cooled to 20 C?
Explanation:
(a)
You know that 100 g water dissolve 487 g sugar.
∴ 100 g of sugar dissolve in
100
g sugar
×
100 g water
487
g sugar
=
20.5 g water
So, 20.5 g of water contain 100 g of sugar at 100 °C.
Answers & Comments
Answer:
Given the following, how do you calculate (a) the mass of water required to dissolve one hundred grams of sugar at 100°C and (b) the amount of sugar that remains in solution when the mixture in (a) is cooled to 20 C?
Explanation:
(a)
You know that 100 g water dissolve 487 g sugar.
∴ 100 g of sugar dissolve in
100
g sugar
×
100 g water
487
g sugar
=
20.5 g water
So, 20.5 g of water contain 100 g of sugar at 100 °C.
(b)
At 20 °C, 20.5 g of water contain
20.5
g water
×
204 g sugar
100
g water
=
41.9 g sugar
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