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yashula
@yashula
August 2021
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Solve thiz sum if u hve dare to it..
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saurabhsemalti
In opl
(pr/2)^2+a^2=r^2......(1)
in triangle omp
b^2+pm^2=r^2......(2)
pq=2pm=2pr
pm=pr
therefore (2) becomes
b^2+(pr) ^2=r^2
substitute value of (pr) from (1) in (2)....
u will get ans
1 votes
Thanks 1
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Answers & Comments
(pr/2)^2+a^2=r^2......(1)
in triangle omp
b^2+pm^2=r^2......(2)
pq=2pm=2pr
pm=pr
therefore (2) becomes
b^2+(pr) ^2=r^2
substitute value of (pr) from (1) in (2)....
u will get ans