Here is ur answer Please mark it as brainliest Abc is an isoseles triangle. AB =ac (given) Also ad =ac So ad =ac Therefore /_ acb =/_ abc Also /_ cad =/_ acd So /_ acb = /_ abc =/_ cad = /_acd (( ((angles opposite to equal sides are equal to each other)) /_cbd +/_cdb +/_ bcd =180 ((ASP)) We write /_ bcd as /_ bca + /_ dca /_ cbd +/_cdb +/_ bca +/_ dca =180 Let cdb qnd other angles = x So x +x+x+x =180 4x =180 X =45 So angle bcd = angle bca +dca X +x =45+45=90
Answers & Comments
Here is ur answer
Please mark it as brainliest
Abc is an isoseles triangle.
AB =ac (given)
Also ad =ac
So ad =ac
Therefore /_ acb =/_ abc
Also /_ cad =/_ acd
So /_ acb = /_ abc =/_ cad = /_acd (( ((angles opposite to
equal sides are equal to each other))
/_cbd +/_cdb +/_ bcd =180 ((ASP))
We write /_ bcd as /_ bca + /_ dca
/_ cbd +/_cdb +/_ bca +/_ dca =180
Let cdb qnd other angles = x
So x +x+x+x =180
4x =180
X =45
So angle bcd = angle bca +dca
X +x =45+45=90