Answer:
2×I2
Step-by-step explanation:
[tex] {s}^{n } = a. {r}^{n - 1} [/tex]
[tex]r = \frac{{s}^{2}}{{s}^{1}} = {4i}^{2} \div {2i}^{2} = 2[/tex]
[tex]matrix \: of \: order \: 2 = {i}^{2 } \times {2}^{2 - 1 } \\ = 2 {i}^{2} [/tex]
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Answers & Comments
Answer:
2×I2
Step-by-step explanation:
[tex] {s}^{n } = a. {r}^{n - 1} [/tex]
[tex]r = \frac{{s}^{2}}{{s}^{1}} = {4i}^{2} \div {2i}^{2} = 2[/tex]
[tex]matrix \: of \: order \: 2 = {i}^{2 } \times {2}^{2 - 1 } \\ = 2 {i}^{2} [/tex]