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mrsonu962
@mrsonu962
August 2021
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solve this question .........
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siddhartharao77
Verified answer
From Figure :
Let the height of the tower be AB.
Given DC = 20m, ACB = 60 degrees and ADB = 60 degrees.
1) From Right angled triangle ACB
Tan 60 = AB/BC
root 3 = AB/BC
AB = root 3 BC ----- (1)
2) From Right angled triangle ADB
Tan 30 = AB/BD
1/root3 = AB/BD
AB = BD/root 3 ----- (2)
From (1) and (2), we get
root 3 BC = BD/root 3
3 BC = BD
3 BC = BC + CD
3 BC = BC + 20
2 BC = 20
BC = 10.
Substitute BC in (1), we get
AB = root 3 * 10
AB = 10 root 3.
The height of the tower = 10 root 3 and the width = 10m.
Hope this helps!
0 votes
Thanks 1
girish21shan
fabulous
siddhartharao77
Thank You
girish21shan
sir how are improve your maths
siddhartharao77
Sorry.. Even I am not so perfect.
girish21shan
but better than something
siddhartharao77
Yes.
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Answers & Comments
Verified answer
From Figure :Let the height of the tower be AB.
Given DC = 20m, ACB = 60 degrees and ADB = 60 degrees.
1) From Right angled triangle ACB
Tan 60 = AB/BC
root 3 = AB/BC
AB = root 3 BC ----- (1)
2) From Right angled triangle ADB
Tan 30 = AB/BD
1/root3 = AB/BD
AB = BD/root 3 ----- (2)
From (1) and (2), we get
root 3 BC = BD/root 3
3 BC = BD
3 BC = BC + CD
3 BC = BC + 20
2 BC = 20
BC = 10.
Substitute BC in (1), we get
AB = root 3 * 10
AB = 10 root 3.
The height of the tower = 10 root 3 and the width = 10m.
Hope this helps!