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this way in all questions of q no. 1 subtract from 90°, because sum of two angles form 90° , which is termed as complementary angle. each of them are called complement of other.
2. i. 180°- 110°= 70°
here in all questions subtract from 180°. because here sum of two angles form 180° , which is termed as supplementary angle. each of them are called supplement of other.
3. aoc = cod; cod= doe; doe= eod
adjacent angle which has one common arm.
4. i. POR= ROQ; POR= POS
II. POS= ROQ; POR= SOQ
5. XOZ = 180°- 45°= 135°( Linear pair means two angles sum 180)
Answers & Comments
Answer. <XOZ = (180-45)°
= 135°
as <XOZ and <ZOY are linear pairs.
Answer:
1. i. 90° -62°= 28° ; ii. 90°- 43°= 47°
Step-by-step explanation:
this way in all questions of q no. 1 subtract from 90°, because sum of two angles form 90° , which is termed as complementary angle. each of them are called complement of other.
2. i. 180°- 110°= 70°
here in all questions subtract from 180°. because here sum of two angles form 180° , which is termed as supplementary angle. each of them are called supplement of other.
3. aoc = cod; cod= doe; doe= eod
adjacent angle which has one common arm.
4. i. POR= ROQ; POR= POS
II. POS= ROQ; POR= SOQ
5. XOZ = 180°- 45°= 135°( Linear pair means two angles sum 180)
6. I. aoc= dob
ii. coa= Aod
III. cob= bod; coa= aoe; aoe= eod; eod= dob
7. soq= 130°[vertically opposite angles]
POS= 50°( linear pair)
roq= 50° ( vertically opposite angles)
8i. x= 180°- 25°=155°( linear pair)
ii.x = 90°- 23°= 67°(complement angle)
III.soq= por
so if soq= 120° ; por =120°
x= 120°-80°= 40°
9.