Rahul96521
Given, Two circle intersect each other at P and Q. To prove APB Congruent AQB Proof. In traiangle APB and AQB .we have AP = AQ. ( each equal to r) AB = AB. ( Common) PB = QB. ( each equal to s) Therefore, ∆APB Is Congruent to ∆ AQB.
Proved.
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vyomgupta
This is your answer . plz mark it as brainlist answer.
Answers & Comments
Two circle intersect each other at P and Q.
To prove APB Congruent AQB
Proof. In traiangle APB and AQB .we have
AP = AQ. ( each equal to r)
AB = AB. ( Common)
PB = QB. ( each equal to s)
Therefore, ∆APB Is Congruent to ∆ AQB.
Proved.