Answer:
First, let's multiply the first equation by 2 and the second equation by 3 to make the coefficients of y the same in both equations:
4x + 6y = 22
12x - 6y = 18
Now, we can add these two equations together:
16x = 40
Then, we can solve for x by dividing both sides by 16:
x = 40 / 16 = 2.5
Now that we have x, we can substitute it into the first equation to solve for y:
2(2.5) + 3y = 11
5 + 3y = 11
3y = 11 - 5 = 6
y = 6 / 3 = 2
So, the solution to the system of equations is x = 2.5 and y = 2.
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Answers & Comments
Answer:
First, let's multiply the first equation by 2 and the second equation by 3 to make the coefficients of y the same in both equations:
4x + 6y = 22
12x - 6y = 18
Now, we can add these two equations together:
16x = 40
Then, we can solve for x by dividing both sides by 16:
x = 40 / 16 = 2.5
Now that we have x, we can substitute it into the first equation to solve for y:
2(2.5) + 3y = 11
5 + 3y = 11
3y = 11 - 5 = 6
y = 6 / 3 = 2
So, the solution to the system of equations is x = 2.5 and y = 2.