Answer:
a) mKET = 30 and mIKT = 75
b) KI= 7 and SE = 6.5
c)20?
a) <KIS = 75
<ITK = 30
<IKT = 90 - <KIS = 90 - 75 = 15°
<KET = 180 - (<IKT + <ITK) = 180 - (30 + 15) = 135°
b)
KE = KI = 7
SE = (1/2)(IE) = (1/2)(13)= 13/2
c)
area = ((2)(IS))(KT)/2 = ((2)(5)(15))/2 = 75 cm²
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Answers & Comments
Answer:
a) mKET = 30 and mIKT = 75
b) KI= 7 and SE = 6.5
c)20?
a) <KIS = 75
<ITK = 30
<IKT = 90 - <KIS = 90 - 75 = 15°
<KET = 180 - (<IKT + <ITK) = 180 - (30 + 15) = 135°
b)
KE = KI = 7
SE = (1/2)(IE) = (1/2)(13)= 13/2
c)
area = ((2)(IS))(KT)/2 = ((2)(5)(15))/2 = 75 cm²
make sure to brainliest this answer so i can notice your next question :)