Verified answer

[tex]The \: given \: system \: of \\ equations \: is[/tex]

[tex]2x + y - 35 = 0 \\ \\ x + 4y - 65 = 0[/tex]

[tex] \frac{x}{[1 \times ( - 65) ] -[4 \times ( - 35) ] } \\ \\ = \frac{ - y}{[ 2 \times ( - 65)] - 3\times ( - 35)} [/tex]

[tex] \frac{x}{ - 65 + 140} = \frac{ - y}{ - 130 + 105} \\ \\ = \frac{1}{8 - 3} [/tex]

[tex] \frac{x}{75} = \frac{y}{25} = \frac{1}{5} \\ \\ x = \frac{75}{5} = 15 \\ \\ y = \frac{25}{5} \\ \\ y = 5[/tex]

[tex]Hence, \: the \: solution \: of \: the \\ given \: system \: of \\ equations \: is \\ \\ x = 15 \\ \\ y = 5[/tex]

Question:-

➦ Solve the following system of equation by cross multiplication:

2x+y -35=0

3x+4y-65 = 0

Correct answer:-

➦ Refer to the below mentioned attachment...!!! :)

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