Answer:
let the equations are :
3x + 2y = 11 and 2x - y = 5
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Step-by-step explanation:
[tex] \sf 3x + 2y = 11 \times 2 \\ \sf2x - y = 5 \times 3 \\ \sf6x + 4y = 22 \\ \sf6x + 3y = 15 \\( - ) \: (- ) =( - ) \\ \sf \ change \: the \: signs \\ \sf 6x \: get \: cancled \: out \: \\ \sf therefore \: \\ \sf y = 7 \\ \sf substitute \: y \: value \: in \: the \: eqn \\ \sf 2x - y = 5 \\ \sf 2x - 7 = 5 \\ \sf 2x = 5 + 7 \\ \sf2x = 12 \\ \sf x = \frac{12}{2} \\ \sf x = 6[/tex]
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Answers & Comments
Answer:
let the equations are :
3x + 2y = 11 and 2x - y = 5
________________________________
Step-by-step explanation:
[tex] \sf 3x + 2y = 11 \times 2 \\ \sf2x - y = 5 \times 3 \\ \sf6x + 4y = 22 \\ \sf6x + 3y = 15 \\( - ) \: (- ) =( - ) \\ \sf \ change \: the \: signs \\ \sf 6x \: get \: cancled \: out \: \\ \sf therefore \: \\ \sf y = 7 \\ \sf substitute \: y \: value \: in \: the \: eqn \\ \sf 2x - y = 5 \\ \sf 2x - 7 = 5 \\ \sf 2x = 5 + 7 \\ \sf2x = 12 \\ \sf x = \frac{12}{2} \\ \sf x = 6[/tex]
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