Solve the following quadratic equations by factoring.
1.) x² + 4x - 5 = 0
2.) 4a² + 12a + 8 = 0
3.) x² + 6x + 5 = 0
4.) x² - 8x + 7 = 0
1.) x² + 4x - 5 = 0
2.) 4a² + 12a + 8 = 0
3.) x² + 6x + 5 = 0
4.) x² - 8x + 7 = 0
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Answer:
1. x = -5, x = 1
2. a = -2, a = -1
3. x = -5, x = -1
4. x = 7, x = 1
Step-by-step explanation:
1. x² + 4x - 5 = 0
(x + 5)(x - 1) = 0
x = -5, x = 1
2. 4a² + 12a + 8 = 0
(2a + 4)(2a + 2) = 0
2a + 4 = 0
2a = -4; a = -2
2a + 2 = 0
2a = -2; a = -1
3. x² + 6x + 5 = 0
(x + 5)(x + 1) = 0
x = -5, x = -1
4. x² - 8x + 7 = 0
(x - 7)(x - 1) = 0
x = 7, x = 1