solve the following quadratic equations by factoring and the results by substituting the roots of variable
1). x² + 7x = 0
2). x² - 5x = 0
3). t² + 8t + 16 = 0
4). h² + 3h = 30
5). x² - 20 = 8x
6). 2x² - 6x = 0
7). x² - 5x = 24
8). x² + 22x + 121 = 0
9). 2x² - 3x + 1 = 0
10). 3x² - 5x = 0
1). x² + 7x = 0
2). x² - 5x = 0
3). t² + 8t + 16 = 0
4). h² + 3h = 30
5). x² - 20 = 8x
6). 2x² - 6x = 0
7). x² - 5x = 24
8). x² + 22x + 121 = 0
9). 2x² - 3x + 1 = 0
10). 3x² - 5x = 0
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Answer:
Step-by-step explanation:
1.) x ( x + 7) = 0
x = 0, x = -7
2.) x( x - 5) = 0
x= 0, x = 5
3.) t² + 8t + 16
( t + 4 )( t + 4)
t = - 4
4.) h² + 3h = 30
h² + 3h - 30 = 0
I don't think this one is factorable.
5.) x^2-8x-20=0
(x+2)(x-10)
x = -2, x = 10
6.) 2x^2 - 6 x = 0
2x ( x - 3) = 0
x = 0, x = 3
7.) x^2 - 5x - 24 = 0
(x + 3)(x - 8) = 0
x = -3, x + 8
8.) x² + 22x + 121 = 0
(x + 11)(x + 11)
x = -11
9.) 2x² - 3x + 1 = 0
( 2x - 1 )(x - 1)
x = 1/2 or 0.5, x = 1
10.) 3x² - 5x = 0
x(3x - 5) = 0
x= 0, x = 3/5 or 0.6
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