solve the following quadratic equation by factoring
1)t²+8t=-16
2)(x+2)²=16
3)x²-9=0
4)4x²-9=0
5)2x²-4x+2=0
1)t²+8t=-16
2)(x+2)²=16
3)x²-9=0
4)4x²-9=0
5)2x²-4x+2=0
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Answer:
1) t² + 8t = -16
t² + 8t + 16 = 0
(t + 4)(t + 4)
2) (x + 2)² = 16
x² + 4x + 4 - 16 = 0
x² + 4x - 12 = 0
(x - 2)(x + 6)
3) x² - 9 = 0
(x - 3)(x + 3)
4) 4x² - 9 = 0
(2x - 3)(2x + 3)
5) 2x² - 4x + 2 = 0
(2x - 2)(x - 1)