Solve the following problems.
1) Thrice the square root of a number is 12. Find the number.
2) The area of a triangle is 20 in^2. If the height is twice as long as its base, how long are the base and the height of the triangle?
help me fleece- T_T
stan aespa! ^_^
1) Thrice the square root of a number is 12. Find the number.
2) The area of a triangle is 20 in^2. If the height is twice as long as its base, how long are the base and the height of the triangle?
help me fleece- T_T
stan aespa! ^_^
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Answer:
1. 16
2. Height = 2√20 inch
Base = √20 inch
Solution:
1.
3√x = 12
(3√x)/3 = (12)/3
√x = 4
(√x)² = (4)²
x = 16
2.
Height = 2x
Base = x
Area of Triangle = 20 in²
Formula for Area of Triangle = bh/2
(x)(2x)/2 = 20
2x²/2 = 20
x² = 20
x = √20
Height = 2x = 2√20 inch
Base = x = √20 inch