Answer:

AREA OF COMPOSITE TRIANGLES

PROBLEM

A figure is made up of three triangles. Each triangle has a base of 6 inches and a height of 4 inches. What is the combined area of all three triangles?

ANSWER:

From the given problem, we will first compute only the area of one triangle:

The formula for finding the area of a triangle is as follows:

\boxed{\rm Area = \dfrac{bh}{2}}Area=2bh

where:

b stands for the base and

h stands for height.

Now, we gonna substitute them to their corresponding values.

We have:

6 inches for the base and

4 inches for the height.

After substituting them, we will next evaluate them by the indicated operation.

Solution:

\begin{gathered}\begin{aligned}A & = \dfrac{(6)(4)}{2}\\& = \dfrac{24}{2}\\& = \boxed{12\: sq. \: inch.}\end{aligned}\end{gathered}A=2(6)(4)=224=12sq.inch.

Lastly, we will multiply the answer by 3.

\boxed{12 \: sq. \: inch. \times 3 = 36 \: sq. \: inch.}12sq.inch.×3=36sq.inch.

Answer:

Therefore, the combined area of all (three) triangles is 36 sq. inches.

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