Step-by-step explanation:
[tex]\sf\frac{x+2}{6} - (\frac{11-x}{3} - \frac{1}{4}) = \frac{3x-4}{12} [/tex]
[tex]\sf\frac{x+2}{6} - ( \frac{44-4x-3}{12}) = \frac{3x-4}{12} [/tex]
[tex]\sf\frac{x+2}{6} - ( \frac{41-4x}{12}) = \frac{3x-4}{12}[/tex]
[tex]\sf\frac{2x+4-41+4x}{12} = \frac{3x-4}{12}[/tex]
[tex]\sf\frac{6x-37}{12} = \frac{3x-4}{12}[/tex]
[tex]\sf{6x−37=3x−4}[/tex]
[tex]\sf{3x=333x=33}[/tex]
[tex]\\x= \frac{33}{3}[/tex]
[tex]\sf\fbox\red{x=11x=11}[/tex]
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
Verified answer
Step-by-step explanation:
[tex]\sf\frac{x+2}{6} - (\frac{11-x}{3} - \frac{1}{4}) = \frac{3x-4}{12} [/tex]
[tex]\sf\frac{x+2}{6} - ( \frac{44-4x-3}{12}) = \frac{3x-4}{12} [/tex]
[tex]\sf\frac{x+2}{6} - ( \frac{41-4x}{12}) = \frac{3x-4}{12}[/tex]
[tex]\sf\frac{2x+4-41+4x}{12} = \frac{3x-4}{12}[/tex]
[tex]\sf\frac{6x-37}{12} = \frac{3x-4}{12}[/tex]
[tex]\sf{6x−37=3x−4}[/tex]
[tex]\sf{3x=333x=33}[/tex]
[tex]\\x= \frac{33}{3}[/tex]
[tex]\sf\fbox\red{x=11x=11}[/tex]