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Answer:

To solve the equations ax + by = c and bx – ay = 0, we can use the substitution method.

First, we will solve the second equation for y:

bx – ay = 0

y = (bx)/a

Now, we will substitute y into the first equation:

ax + by = c

ax + b(bx/a) = c

ax + b²x/a = c

(a + b²/a)x = c

x = c/(a + b²/a)

Now, we can substitute x into the second equation to solve for y:

bx – ay = 0

b(c/(a + b²/a)) – a(y) = 0

by = ac/(a + b²/a)

y = ac/(a + b²/a)b

Therefore, the solutions to the equations ax + by = c and bx – ay = 0 are .....x = c/(a + b²/a) and y = ac/(a + b²/a)b.

Hope it helps you bro! :>

Answer:

bx – ay = 0

y = (bx)/a

ax + by = c

ax + b(bx/a) = c

ax + b²x/a = c

(a + b²/a)x = c

x = c/(a + b²/a)

bx – ay = 0

b(c/(a + b²/a)) – a(y) = 0

by = ac/(a + b²/a)

y = ac/(a + b²/a)b

Therefore, the solutions is ax + by = c and bx – ay = 0 are .....x = c/(a + b²/a) and y = ac/(a + b²/a)b.