BM and DN are both perpendiculars to the line segment AC. also BM = DN. prove that AC bisects BD.
In △DON & △BOM
DN = BM (Given)
DON = BOM (Vertically Opposite angle)
∠N = ∠M (Each 90°)
By AAS rule △BOM ≅ △DON
BO = DO
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Question :
BM and DN are both perpendiculars to the line segment AC. also BM = DN. prove that AC bisects BD.
Given :
To Prove :
Proof :
In △DON & △BOM
DN = BM (Given)
DON = BOM (Vertically Opposite angle)
∠N = ∠M (Each 90°)
By AAS rule △BOM ≅ △DON
BO = DO
So, AC Bisect BD
❖Proved❖
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