Step-by-step explanation:
6(sin
6
θ+cos
θ)−9(sin
4
θ)+4
=6(sin
2
θ)(sin
θ−sin
θcos
=6sin
θ+6cos
θ−6sin
θ−9sin
θ−9cos
θ+4
=−3(sin
θ+2sin
θ)
+4=−3+4=1
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Verified answer
Step-by-step explanation:
6(sin
6
θ+cos
6
θ)−9(sin
4
θ+cos
4
θ)+4
=6(sin
2
θ+cos
2
θ)(sin
4
θ+cos
4
θ−sin
2
θcos
2
θ)−9(sin
4
θ+cos
4
θ)+4
=6sin
4
θ+6cos
4
θ−6sin
2
θcos
2
θ−9sin
4
θ−9cos
4
θ+4
=−3(sin
4
θ+cos
4
θ+2sin
2
θcos
2
θ)+4
=−3(sin
2
θ+cos
2
θ)
2
+4=−3+4=1