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Given, AB || DE . To find angle ACD, Construction: Draw a line pushing through point C such that the line is parallel to both AB and DE. Solution:AngleBAC=AngleACX(alternate angles)....................(1) Angle CDE=Angle DCX(alternate angles)..................(2) Adding equations 1 and 2, 35°+53°=88° =>Angle DCA=88° hope it helps...... plz mark it Brainliest if it helps.......!!!!
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AB || DE .
To find angle ACD,
Construction: Draw a line pushing through point C such that the line is parallel to both AB and DE.
Solution:AngleBAC=AngleACX(alternate angles)....................(1)
Angle CDE=Angle DCX(alternate angles)..................(2)
Adding equations 1 and 2,
35°+53°=88°
=>Angle DCA=88°
hope it helps......
plz mark it Brainliest if it helps.......!!!!