Step-by-step explanation:
1)....(x
2
2007
+1)−1. The value of g(2) equals to ....
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Study later
ANSWER
RHS=
(x−1)
(x−1)(x+1)(x
+1)(x
4
+1)....(x
+1)
−1
=
(x
−1)(x
Hence, g(x)⋅(x
(2
2008
−1)
−1)=
−1)−(x−1)
⇒g(x)=
x−1
x
∴g(2)=2
Ans: 2
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Answers & Comments
Step-by-step explanation:
1)....(x
2
2007
+1)−1. The value of g(2) equals to ....
Share
Study later
ANSWER
RHS=
(x−1)
(x−1)(x+1)(x
2
+1)(x
4
+1)....(x
2
2007
+1)
−1
=
(x−1)
(x
2
−1)(x
2
+1)....(x
2
2007
+1)
−1
=
(x−1)
(x
2
2
−1)(x
2
2
+1)....(x
2
2007
+1)
−1
Hence, g(x)⋅(x
(2
2008
−1)
−1)=
(x−1)
(x
2
2008
−1)−(x−1)
⇒g(x)=
x−1
x
∴g(2)=2
Ans: 2
1)....(x
2
2007
+1)−1. The value of g(2) equals to ....
Share
Study later
ANSWER
RHS=
(x−1)
(x−1)(x+1)(x
2
+1)(x
4
+1)....(x
2
2007
+1)
−1
=
(x−1)
(x
2
−1)(x
2
+1)....(x
2
2007
+1)
−1
=
(x−1)
(x
2
2
−1)(x
2
2
+1)....(x
2