Answer:
Let
x+2y
1
=U,
3x−2y
=V⇒
2
U
+
3
5V
=−
⇒3U+10V=−9.........(i)
⇒
4
5U
−
5
3V
=
60
61
⇒75U−36V=61.........(ii)
Equation (I) is multiplied by 25
75U + 250V = -225
75U - 36V = 61
- + -
Subtracting 286V = - 286 V=−1,U=
∴
,
=−1 x + 2y = 3, -3x + 2y = 1
x + 2y = 3
-3x + 2y = 1
+ - - Subtracting 4x = 2 So x=
,y=
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Answers & Comments
Answer:
Let
x+2y
1
=U,
3x−2y
1
=V⇒
2
U
+
3
5V
=−
2
3
⇒3U+10V=−9.........(i)
⇒
4
5U
−
5
3V
=
60
61
⇒75U−36V=61.........(ii)
Equation (I) is multiplied by 25
75U + 250V = -225
75U - 36V = 61
- + -
Subtracting 286V = - 286 V=−1,U=
3
1
∴
x+2y
1
=
3
1
,
3x−2y
1
=−1 x + 2y = 3, -3x + 2y = 1
x + 2y = 3
-3x + 2y = 1
+ - - Subtracting 4x = 2 So x=
2
1
,y=
4
5