Solve each quadratic equation by factoring
1.) 1.) 3x²+12x-15=0
2.) 2x²+23x-25=0
3.) 3x²-5x=-12
4.) 2(3x²-1)=11x
with solutions
kong hindi mo alam wag kana mag answer
1.) 1.) 3x²+12x-15=0
2.) 2x²+23x-25=0
3.) 3x²-5x=-12
4.) 2(3x²-1)=11x
with solutions
kong hindi mo alam wag kana mag answer
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1,) 3x²+12x-15=0
= x²+4x-5=0
= (x-1)(x+5)=0
x-1=0 x+5=0
x=0+1 x=0-5
x=1 x=-5
2,)Use FOIL (First, Outer, Inner Last)
F (2x)(x)= 2x²
O (2x)(-1)= -2x
I (25)(x)= 25x
L (25)(-1)= -25
= 2x²-2x+25x-25 (combine like terms)
= 2x²+23x-25
3,)3x^2 + 5x -12 = 0
We need to solve for x.
We will use the formula to find the roots of the quadratic equations.
We know that:
x = [ -b +- (b^2-4ac)/ 2a
==> x1= ( -5 + 25-4*3*-12)]/2*3
= (-5 + (169) /...
pa brainleats
ac=(-2)(1)=
2(3-1):6
6-2=11x
6-2-11x=11x-11x
6-11x-2=0
x=2,x=
Roots are = and =2