[tex]{\underline{\huge{\overline{\red{\colorbox{black}{Answer:-}}}}}}[/tex]
Sure! Let's solve the equation √(ax+b) = cx+d step by step.
1. Isolate the square root term: √(ax+b) = cx+d
2. Square both sides of the equation: (√(ax+b))^2 = (cx+d)^2
3. Simplify: ax+b = (cx+d)^2
4. Expand the squared term: ax+b = c^2x^2 + 2cdx + d^2
5. Rearrange the equation: c^2x^2 + (2cd-a)x + (d^2-b) = 0
6. This is now a quadratic equation. You can solve it using the quadratic formula or factoring.
I hope this helps! Let me know if you have any other questions.[tex][/tex]
√(ax+b) = cx+d
(ac
(ax+b)= (CX+d)²
ax+b = c²x²+d²+2cdx
ax-2cdx-c²x² = d²-b
[tex] {d}^{2} - b = x(a - 2cd - {c}^{2} x) \\ \\ \frac{({d}^{2} - b)}{(a - 2cd - {c}^{2} x)} = x[/tex]
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Answers & Comments
[tex]{\underline{\huge{\overline{\red{\colorbox{black}{Answer:-}}}}}}[/tex]
Sure! Let's solve the equation √(ax+b) = cx+d step by step.
1. Isolate the square root term: √(ax+b) = cx+d
2. Square both sides of the equation: (√(ax+b))^2 = (cx+d)^2
3. Simplify: ax+b = (cx+d)^2
4. Expand the squared term: ax+b = c^2x^2 + 2cdx + d^2
5. Rearrange the equation: c^2x^2 + (2cd-a)x + (d^2-b) = 0
6. This is now a quadratic equation. You can solve it using the quadratic formula or factoring.
I hope this helps! Let me know if you have any other questions.[tex][/tex]
√(ax+b) = cx+d
(ac
(ax+b)= (CX+d)²
ax+b = c²x²+d²+2cdx
ax-2cdx-c²x² = d²-b
[tex] {d}^{2} - b = x(a - 2cd - {c}^{2} x) \\ \\ \frac{({d}^{2} - b)}{(a - 2cd - {c}^{2} x)} = x[/tex]