A 0.10-kg ball, traveling horizontally at 25 m/s, strikes a wall and rebounds at 19 m/s. What is the magnitude of the change in the momentum of the ball during the rebound?
PLS EXPLAIN WHY W/ SOLUTION
PLS EXPLAIN WHY W/ SOLUTION
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Explanation:
momentum is the product of speed and mass of object. Since we are asked for the change in momentum, that is the momentum after minus momentum before.
P=m(v2-v1)
P=0.1(19-25)
P= -0.6 kgm/s
Negative magnitude niya kasi humina momentum niya after nag strike.