Answer:
Stopping potential=(
λ
hc
−ϕ)/e
=(
330
1240
−2)/e(hc=1240eV−nm)
=(3.75−2)/e
=1.75eV/e
=1.75V
6.E−39
Explanation:
this is the answer shows in calculator..
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Verified answer
Answer:
Stopping potential=(
λ
hc
−ϕ)/e
=(
330
1240
−2)/e(hc=1240eV−nm)
=(3.75−2)/e
=1.75eV/e
=1.75V
Answer:
6.E−39
Explanation:
this is the answer shows in calculator..