let
x = length of tanget
external length of secant = 6
length of secant = 6 + x + 6 = x + 12
x² = (6)(x + 12)
x² = 6x + 72
x² - 6x - 72 = 0
x = 12 and - 6
x = 12cm
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let
x = length of tanget
external length of secant = 6
length of secant = 6 + x + 6 = x + 12
x² = (6)(x + 12)
x² = 6x + 72
x² - 6x - 72 = 0
x = 12 and - 6
x = 12cm
make sure to brainliest this answer so i can notice your next question :)