Answer:
We have,
LHS =
t
a
n
θ
−
c
o
s
i
=
2
⇒
1
e
(
+
)
R
H
S
.
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Answers & Comments
Answer:
We have,
LHS =
t
a
n
θ
−
c
o
t
θ
s
i
n
θ
c
o
s
θ
=
s
i
n
θ
c
o
s
θ
−
c
o
s
θ
s
i
n
θ
s
i
n
θ
c
o
s
θ
=
s
i
n
2
θ
−
c
o
s
2
θ
s
i
n
θ
c
o
s
θ
c
o
s
θ
s
i
n
θ
⇒
LHS =
s
i
n
2
θ
−
c
o
s
2
θ
s
i
n
2
θ
c
o
s
2
θ
⇒
LHS =
s
i
n
2
θ
s
i
n
2
θ
c
o
s
2
θ
−
c
o
s
2
θ
s
i
n
2
θ
c
o
s
2
θ
⇒
LHS =
1
c
o
s
2
θ
−
1
s
i
n
2
θ
⇒
LHS =
s
e
c
2
θ
−
c
o
s
e
c
2
θ
=
(
1
+
t
a
n
2
θ
)
−
(
1
+
c
o
t
2
θ
)
=
t
a
n
2
θ
−
c
o
t
2
θ
=
R
H
S
.