Answer:
Let us consider the problem
s
i
n
2
A
−
B
sin
cos
=
1
sinB
cosB
+
(
)
tan
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Answer:
Let us consider the problem
s
i
n
2
A
−
s
i
n
2
B
sin
A
cos
A
−
sin
B
cos
B
=
1
−
cos
2
A
2
−
1
−
cos
2
B
2
2
sin
A
cos
A
2
−
2
sinB
cosB
2
=
1
−
cos
2
A
−
1
+
cos
2
B
sin
2
A
−
sin
2
B
=
−
(
cos
2
A
−
cos
2
B
)
sin
2
A
−
sin
2
B
=
−
(
−
2
sin
(
2
A
+
2
B
2
)
sin
(
2
A
−
2
B
2
)
)
2
sin
(
2
A
−
2
B
2
)
cos
(
2
A
+
2
B
2
)
=
sin
(
A
+
B
)
cos
(
A
+
B
)
=
tan
(
A
+
B
)