[tex] \frac{x³y² × 3x²y}{2xy} [/tex]
Take out x² and y common
[tex] \frac{ {x}^{2}y(xy \: \times 3) }{2xy} [/tex]
Then, Cut out the common on both numerator and denominator
And the end answer will be
x ( xy × 3 ) / 2
Yes. The last one is correct
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Verified answer
[tex] \frac{x³y² × 3x²y}{2xy} [/tex]
Take out x² and y common
[tex] \frac{ {x}^{2}y(xy \: \times 3) }{2xy} [/tex]
Then, Cut out the common on both numerator and denominator
And the end answer will be
x ( xy × 3 ) / 2
Yes. The last one is correct