The brakes applied to a car produce a deceleration of 6m/s²
.if the car take 2 seconds to stop after the application of brakes calculate the distance it travel during this time
.if the car take 2 seconds to stop after the application of brakes calculate the distance it travel during this time
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u=?
a=-6
t=2sec
by first law of motion
v=u+at
0=u + -6.2
o=u-12
u=12
using third equation of motion
v*2 - U*2=2as
0 - 144 = 2.6.s
-144=-12s
12=s