Answer:
1. The column can support 324 metric tons.
2. The volume is 138 cubic centimeters.
3. The centrifugal force is 43,750 dynes.
Solutions:
1. M = k d⁴ / h²
Formula for k:
k = Mh² / d⁴
k = 64 x 81 / 16
k = 324
Substitute the given values.
M = 324 x 81 / 81
M = 324
The column can support 324 metric tons.
2. v = k t / p
k = v p / t
k = 230 x 20 / 300
k = 46 / 3
v = (46/3 x 270) / 30
v = 138
The volume is 138 cubic centimeters.
3. f = k r m / t²
k = ft² / r m
k = 5000 x 3² / 75 x 6
k = 100
f = 100 x 125 x 14 / 2²
f = 43750
The centrifugal force is 43,750 dynes.
Hope this helps po.
I'm not sure sa answers..
Paki correct po pag may mali :)
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Answers & Comments
Answer:
1. The column can support 324 metric tons.
2. The volume is 138 cubic centimeters.
3. The centrifugal force is 43,750 dynes.
Solutions:
1. M = k d⁴ / h²
Formula for k:
k = Mh² / d⁴
k = 64 x 81 / 16
k = 324
Substitute the given values.
M = 324 x 81 / 81
M = 324
The column can support 324 metric tons.
2. v = k t / p
Formula for k:
k = v p / t
k = 230 x 20 / 300
k = 46 / 3
Substitute the given values.
v = (46/3 x 270) / 30
v = 138
The volume is 138 cubic centimeters.
3. f = k r m / t²
Formula for k:
k = ft² / r m
k = 5000 x 3² / 75 x 6
k = 100
Substitute the given values.
f = 100 x 125 x 14 / 2²
f = 43750
The centrifugal force is 43,750 dynes.
Hope this helps po.
I'm not sure sa answers..
Paki correct po pag may mali :)