show your complete solution write your answer in 1 whole
1.)8.25x10¹⁸ CH20 molecules to moles 2.)8.18 moles of H in NH3 3.)3.67 moles of Zn(OH)2 to g 4.)323 g of CBr4 to mole of CBr4 5.) 12.5g C2H60 to mole of C2H60
1.) 8.25 x 10¹⁸ CH20 molecules is equivalent to 8.25 x 10¹⁸ / 6.022 x 10²³ = 0.00035 moles.
2.) 8.18 moles of H is equivalent to 8.18 / (1 + 3) = 2.046 moles of NH3.
3.) 3.67 moles of Zn(OH)2 is equivalent to 3.67 x (65.39 + 2 x 16.00 + 2 x 1.01) = 221.22 g.
4.) 323 g of CBr4 is equivalent to 323 / (209.89) = 1.54 moles of CBr4.
5.) 12.5 g C2H60 is equivalent to 12.5 / (2 x 12.01 + 6 x 1.01) = 0.837 moles of C2H60.
I hope this helps! If you are satisfied with my answer please mark me as the brainliest. Let me know if you have further questions. And you can also follow me for more answers.
Answers & Comments
Answer:
1.) 8.25 x 10¹⁸ CH20 molecules is equivalent to 8.25 x 10¹⁸ / 6.022 x 10²³ = 0.00035 moles.
2.) 8.18 moles of H is equivalent to 8.18 / (1 + 3) = 2.046 moles of NH3.
3.) 3.67 moles of Zn(OH)2 is equivalent to 3.67 x (65.39 + 2 x 16.00 + 2 x 1.01) = 221.22 g.
4.) 323 g of CBr4 is equivalent to 323 / (209.89) = 1.54 moles of CBr4.
5.) 12.5 g C2H60 is equivalent to 12.5 / (2 x 12.01 + 6 x 1.01) = 0.837 moles of C2H60.
I hope this helps! If you are satisfied with my answer please mark me as the brainliest. Let me know if you have further questions. And you can also follow me for more answers.