Answer:

Step-by-step explanation:

let,

g(x)= x+1 and      ... (1)  and g(x)= 0

f(x)= x³-13x²+32x-20       ...(2)

from (1) we know, x-1= 0

therefore, x=1

substituting x=1 in f(x),

f(1)= (1)³ - 13(1)²+32*1-20

     =  1 - 13 + 32- 20

     = -12+12

      = 0

since f(1)=0 we know that (x-1) is a factor of f(x).

thank you, please mark brainliest.

Answer:

Step-by-step explanation: