Verified answer

Answer:

when x = 1 and y = 1

4x1 - 1 - 3 = 0

4-4 = 0

0 = 0

when x = 2 and y = 5

4x2 - 5 - 3 = 0

8 - 5 -3 = 0

8-8 = 0

0 = 0

[tex] \underline{\underline{ \large\blue{ \mathcal{EQUATION}}}} = > [/tex]

[tex] \orange{ \bf \: 4x - y - 3 = 0}[/tex]

Case 1)

[tex] \star \sf \: x = 1 \: and \: y = 1 \star[/tex]

Put these values in equation:-

[tex]4(1) - (1) - 3 = 0 \\ 4 - 1 - 3 = 0 \\ 4 - 4 = 0 \\ \purple{\boxed{ 0 = 0}}[/tex]

Case 2)

[tex] \star \sf \: x = 2 \: and \: y = 5 \star[/tex]

Put these value in equation:-

[tex]4(2) - (5) - 3 = 0 \\ 8 - 5 - 3 = 0 \\ 8 - 8 = 0 \\ \green{\boxed{ 0 = 0}}[/tex]

As, in both cases,

LHS = RHS

So,

Both are the solutions of the given equation

Hope this may help!

[tex] \red{ \mathbb{PLZ \: THANKs}}[/tex]