Answer:
Given A(0,4,1) B(2,3,−1) C(4,5,0) D(2,6,2)
AB=
BC=(2−4)^2+(3−5)2+(−1−0)2=3
CD=(4−2)2+(5−6)2+(0−2)2=3
DA=(2−0)2+(6−4)2+(2−1)2=3
∴AB=BC=CD=DA
AC=(0−4)2+(4−5)2+(1−0)2=18
BD=(2−2)2+(3−6)
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Solution:
Given A(0,4,1) B(2,3,−1) C(4,5,0) D(2,6,2)
AB=
[tex] {(0−2)}^{2} + {(4−3)}^{2} + {(1 + 1)}^{2} = 3[/tex]
BC=(2−4)^2+(3−5)2+(−1−0)2=3
CD=(4−2)2+(5−6)2+(0−2)2=3
DA=(2−0)2+(6−4)2+(2−1)2=3
∴AB=BC=CD=DA
AC=(0−4)2+(4−5)2+(1−0)2=18
BD=(2−2)2+(3−6)