A student starts a food fight by throwing 0.8 kg burrito at some girl he likes.He throws it kind of hard so he accelerate it at 5.3 m/s².How much force did this take?
Answers & Comments
ntnttblb
M = mass of burrito thrown by the student = 0.5 kg
m = mass of burrito thrown by the student = 0.5 kg a = acceleration of the burrito thrown by the student = 3 m/s² F = force applied by the student on the burrito = ? According to newton's second law , the net force on an object is the product of its mass and acceleration. it is given as F = ma inserting the values F = (0.5) (3) F = 1.5 N hence the net force on the burrito comes out to be 1.5 N
Answers & Comments
m = mass of burrito thrown by the student = 0.5 kg
a = acceleration of the burrito thrown by the student = 3 m/s²
F = force applied by the student on the burrito = ?
According to newton's second law , the net force on an object is the product of its mass and acceleration. it is given as
F = ma
inserting the values
F = (0.5) (3)
F = 1.5 N
hence the net force on the burrito comes out to be 1.5 N