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Mohit8745
@Mohit8745
July 2022
2
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show by means of graphical method that :- V=U+AT
where the symbol have their usual meaning?
Answers & Comments
anshika1020
Hello..
initial velocity of the object = u
object moving with uniform acceleration, a.
object reaches at point B
time, t
final velocity becomes, v
Draw line parallel to xaxis DA from D where object starts moving.
Draw another line BA from B parallel to y-axis
meets at E at y-axis.
Let OE = time, t
Now, as we had seen the graph,
BE = AB + AE
⇒ v = DC + OD (Since, AB = DC and AE = OD)
⇒ v = DC + u (Since, OD = u)
⇒ v = DC + u ------------------- (i)
Now, Acceleration (a) =Change in velocity/Time taken
⇒a=v−u/t
⇒a=OC−OD/t=DC/t
⇒at=DC -----(ii)
By substituting the value of DC from (ii) in (i) we get
v=at+uv=at+u
⇒v=u+at
(ii) These values have their particular name to derive equations or to write in answer or explanation
92 votes
Thanks 139
tyagiabhinay16
Answer:
v=u+at v=u+at v=u+at v=u+at v=u+at
9 votes
Thanks 6
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Answers & Comments
initial velocity of the object = u
object moving with uniform acceleration, a.
object reaches at point B
time, t
final velocity becomes, v
Draw line parallel to xaxis DA from D where object starts moving.
Draw another line BA from B parallel to y-axis
meets at E at y-axis.
Let OE = time, t
Now, as we had seen the graph,
BE = AB + AE
⇒ v = DC + OD (Since, AB = DC and AE = OD)
⇒ v = DC + u (Since, OD = u)
⇒ v = DC + u ------------------- (i)
Now, Acceleration (a) =Change in velocity/Time taken
⇒a=v−u/t
⇒a=OC−OD/t=DC/t
⇒at=DC -----(ii)
By substituting the value of DC from (ii) in (i) we get
v=at+uv=at+u
⇒v=u+at
(ii) These values have their particular name to derive equations or to write in answer or explanation
Answer:
v=u+at v=u+at v=u+at v=u+at v=u+at