Answer:
In the given figure, x=45
0
(Alternate angles)
Similarly, z=55
But x+y+z=180
(Angles on the one side of a straight line)
⇒45
+y+55
=180
⇒y+100
⇒y=180
−100
=80
x=45
,y=80
,z=55
In ∆DEF
angle D + angle E + angle F = 180°
60° + angle E + 35° = 180°
angle E = 180°-95°
= 85°
z + 85° = 180° (linear pair)
z = 180°-85°
= 95°
35° + n = 180°
n = 145°
x + 60° = 145°
x = 145°-60°
x = 85°
Now,
y = angle DFE = 35° (alternate interior angle)
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Answers & Comments
Answer:
In the given figure, x=45
0
(Alternate angles)
Similarly, z=55
0
(Alternate angles)
But x+y+z=180
0
(Angles on the one side of a straight line)
⇒45
0
+y+55
0
=180
0
⇒y+100
0
=180
0
⇒y=180
0
−100
0
=80
0
x=45
0
,y=80
0
,z=55
0
Verified answer
Answer:
In ∆DEF
angle D + angle E + angle F = 180°
60° + angle E + 35° = 180°
angle E = 180°-95°
= 85°
z + 85° = 180° (linear pair)
z = 180°-85°
= 95°
35° + n = 180°
n = 145°
x + 60° = 145°
x = 145°-60°
x = 85°
Now,
y = angle DFE = 35° (alternate interior angle)