She has a rectangular pool that has a length of 3 feet longer that its width. The area of the rectangular pool is 54 square feet.
1. How to solve this problem?
2. What is the length?
3. What are the dimensions of Lea's pool?
1. How to solve this problem?
2. What is the length?
3. What are the dimensions of Lea's pool?
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Answer:
w=6 l=9
9ft×6ft
Step-by-step explanation:
l=w+3, l×w=54
substitute the value of l:
(w+3)w=54 w>0
w²+3w=54
w²+3w-54=0
(w+9)(w-6)=0
w= -9,6
therefore,w=6
l=w+3
l=6+3
l=9