In this problem, we are asked to list all the factors of 45 in a set. To make things simple, I will list them based on the Roster Method, where you just list all the elements and separate them with commas.
Let's figure out first the factors of 45.
We know that all num|bers have a factor of 1. Therefore, we know that 1 and 45 are factors of 45.
Now, we just need to count up and determine if 45 is divisible by that num|ber.
Let's start first with 2. 45 is not even, so 2 is not a factor. Using this, we can also know that 45 has no even factor.
Let's check 3. 4+5=9, and 9 is divisible by 3. Thus, 3 is a factor of 45. This also has an inverse factor 15 since 3 times 15 equals 45.
Finally, let's check 5. 45 ends with 5 so it is divisible by 5. Thus, 5 is also a factor of 45. This has an inverse factor of 9.
The final step is to just list the factors as elements in a set.
Therefore, the final answer is {1, 3, 5, 9, 15, 45}.
Answers & Comments
Verified answer
Answer:
{1, 3, 5, 9, 15, 45}
Step-by-step explanation:
In this problem, we are asked to list all the factors of 45 in a set. To make things simple, I will list them based on the Roster Method, where you just list all the elements and separate them with commas.
Let's figure out first the factors of 45.
We know that all num|bers have a factor of 1. Therefore, we know that 1 and 45 are factors of 45.
Now, we just need to count up and determine if 45 is divisible by that num|ber.
Let's start first with 2. 45 is not even, so 2 is not a factor. Using this, we can also know that 45 has no even factor.
Let's check 3. 4+5=9, and 9 is divisible by 3. Thus, 3 is a factor of 45. This also has an inverse factor 15 since 3 times 15 equals 45.
Finally, let's check 5. 45 ends with 5 so it is divisible by 5. Thus, 5 is also a factor of 45. This has an inverse factor of 9.
The final step is to just list the factors as elements in a set.
Therefore, the final answer is {1, 3, 5, 9, 15, 45}.
Hope this helps!
#CarryOnLearning