Answer:
Average speed =
(
πm
8RT
)
Most probable speed =
m
2RT
Average speed at T
1
K = MP speed at T
2
KforCO
=
T
4
π
------(i)
Also for CO
u
mp
=9×10
44
2×8.314×10
7
×T
By eq (1) We get
=2143K
=1684K
Hence answer is (C)
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Answers & Comments
Answer:
Average speed =
(
πm
8RT
)
Most probable speed =
(
m
2RT
)
Average speed at T
1
K = MP speed at T
2
KforCO
2
(
πm
8RT
1
)
=
(
m
2RT
2
)
T
2
T
1
=
4
π
------(i)
Also for CO
2
u
mp
=
(
m
2RT
)
=9×10
4
=
44
2×8.314×10
7
×T
2
=9×10
4
By eq (1) We get
T
2
=2143K
T
1
=1684K
Hence answer is (C)