A ball is thrown vertically upward with a velocity of 40 m/sec. The height
s(t) of the ball above the building after t seconds is given by the function
s(t) = 40t – 5t2.
a. How long will it take the object to reach the maximum height?
b. What maximum height will the object reach?
c. Find the time at which the object is on the ground.
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Answer:
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