Answer:

Let’s review the 4 basic kinematic equations of motion for constant acceleration (this is a lesson – suggest you commit these to memory):

s = ut + ½ at^2 …. (1)

v^2 = u^2 + 2as …. (2)

v = u + at …. (3)

s = (u + v)t/2 …. (4)

where s is distance, u is initial velocity, v is final velocity, a is acceleration and t is time.

In this case, we know u = 12m/s, v = 0, t = 36s and we want to find the acceleration, a. So, we use equation (3)

v = u + at, so 0 = 12 + 36a

so a = -12/36 = -1/3m/s^2 or -0.333m/s^2

Explanation:

❀⊱─━━━━━━⊱ ༻ ● ༺ ⊰━━━━━━─⊰❀

• ఌ︎☾︎__ kim__☽︎ ఌ︎ •

ⓒ︎Ⓞ︎Ⓡ︎Ⓡ︎Ⓔ︎Ⓒ︎Ⓣ︎Ⓛ︎Ⓨ︎

«« ❥︎ ----- StaySafe »»