Answer:

Answer:

1. The velocity of the car is 25 m/s

2. The mass of the bullet is 0.075 kg

3. The velocity of the boy and the bicycle is 3.11 m/s

4. The momentum of the jeepney is 40,000 kg·m/s

The momentum of the truck is is 80,000 kg·m/s

Explanation:

In our case, we are to solve the velocity, mass and momentum in four different scenarios about momentum.

For the formula, we will use:

p = mv

where

p is the momentum of an object, unit is in kg·m/s

m is the mass of the object, unit is in kg

v is the velocity of the object, unit is in m/s

For the given information

1. m = 1200 kg

p = 30,000 kg·m/s

v = ?

2. p = 1.50 kg·m/s

v = 20 m/s

m = ?

3. m1 = 30 kg

m2 = 7 kg

p = 116 kg·m/s

v = ?

4. mj = 2000 kg

mt = 4000 kg

v = 72 km/h

pj = ?, pt = ?

Solving the problem

1. For the first problem, let us use the formula for momentum to solve for the velocity of the car.

p = mv

30,000 kg.m/s=(1200kg)v30,000kg.m/s=(1200kg)v

v = \frac{30,000 kg.m/s}{1200kg}v=

1200kg

30,000kg.m/s

v = 25 m/s

2. Next, let us solve for the mass of the bullet. Again, let us use the formula for momentum then substitute the given information.

p = mv

1.50 kg·m/s = m(20 m/s)

divide both sides of the equation by 20 m/s, we have:

m = \frac{1.50kg.m/s}{20m/s}m=

20m/s

1.50kg.m/s

m = 0.075 kg

3. Next is to solve for the velocity of the boy and the bicycle.

p = (m1 + m2)v

115 kg·m/s = (30 kg + 7 kg) v

115 = 37 v

Divide both sides of the equation by 37, we have:

v = 115/37

v = 3.11 m/s

4. For the last problem, we will convert first v = 72 km/h to m/s, we have:

v = 72 km/h x 1000m/1 km x 1 hour/3600 s = 20 m/s

Now, we are ready to solve for the momentum of each object.

For the jeepney:

pj = (mj) v

pj = (2000 kg) (20 m/s)

pj = 40,000 kg·m/s

For the truck:

pt = (mt) v

pt = (4000 kg)(20 m/s)

pt = 80,000 kg·m/s