The amount of ethyl alcohol present in a 50 ml bottle of 70% alcohol solution is 35 ml
(T) Total Volume of Solution: 50 ml
(P) Percentage by volume of solute: 70%
(V) volume of solute
(T) = Total Volume of Solution
(P) = Percentage by volume of solute
(V) = Volume of solute
V = P x T/100
V = 50 x 70 / 100
V = 3,500 / 100
V = 35 ml
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Answer:
The amount of ethyl alcohol present in a 50 ml bottle of 70% alcohol solution is 35 ml
Explanation:
Given:
(T) Total Volume of Solution: 50 ml
(P) Percentage by volume of solute: 70%
Required
(V) volume of solute
Solution:
(T) = Total Volume of Solution
(P) = Percentage by volume of solute
(V) = Volume of solute
V = P x T/100
V = 50 x 70 / 100
V = 3,500 / 100
V = 35 ml