Given : a= 1.62m/s²
h= 1.50 m
vi= 0m/s
Asked : t=
use equation G
h= –(vit +½ agt²)
pa help po need ko po ngayon
sana masagot
h= 1.50 m
vi= 0m/s
Asked : t=
use equation G
h= –(vit +½ agt²)
pa help po need ko po ngayon
sana masagot
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Verified answer
Answer:
To solve this problem, we can use the equation:
h = - (vit + 1/2 a gt^2)
where h is the initial height (1.50 m), vi is the initial velocity (0 m/s), a is the acceleration of gravity on the moon (1.62 m/s^2), and t is the time it takes for the ball to fall to the surface of the moon.
Plugging in the values, we get:
1.50 = - (0)t + 1/2 (1.62) t^2
Simplifying the equation:
0.81t^2 = 1.50
t^2 = 1.85
t = sqrt(1.85)
t ≈ 1.36 seconds
Therefore, it takes approximately 1.36 seconds for the ball to fall to the surface of the moon.