Answer:
Sanika present age is 11 years
her mother's age after 10 years is= 49
Step-by-step explanation:
let ger mother age be x then,
Sanika is 28 years young then her mother it means
sanika age is (x-28)
sum of both age = 50
(x-28) + x = 50
2x - 28 = 50
2x = 50+ 28
x = 78/2
× = 39
Sanika's present age is 11
The age of a mother after ten years is 49
Let the age of Sanika's mother be x
They have given that Sanika is 28 years younger than her mother
Therefore Sanika's age is x +( x-28)
The sum of the ages of Sanika and her mother = 50
x +(x-28) = 50
2x = 50+28
x = 39
Therefore Mother's age = 39
Sanika's age = 39 - 28
Therefore Sanika's age = 11
Hence Mother's age after ten years is 49.
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Answers & Comments
Answer:
Sanika present age is 11 years
her mother's age after 10 years is= 49
Step-by-step explanation:
let ger mother age be x then,
Sanika is 28 years young then her mother it means
sanika age is (x-28)
sum of both age = 50
(x-28) + x = 50
2x - 28 = 50
2x = 50+ 28
x = 78/2
× = 39
Answer:
Sanika's present age is 11
The age of a mother after ten years is 49
Step-by-step explanation:
Let the age of Sanika's mother be x
They have given that Sanika is 28 years younger than her mother
Therefore Sanika's age is x +( x-28)
The sum of the ages of Sanika and her mother = 50
x +(x-28) = 50
2x = 50+28
x = 78/2
x = 39
Therefore Mother's age = 39
Sanika's age = 39 - 28
Therefore Sanika's age = 11
Hence Mother's age after ten years is 49.