Question:

Sally adds

3.13

moles of argon to a

5.29

liter balloon that already contained

2.51

moles of argon. What is the volume of the balloon after the addition of the extra gas?

Mole-Volume Relationship:

The mole and volume relationship is directly proportional. Avogadro's law gives this proportional relationship between the moles and volume. That is, the ratio of volume to moles is constant.

Answer and Explanation: 1

Given Data:

The moles of argon added is 3.13 mol.

The initial moles of argon is

n

1

=

2.51

m

o

l

.

The initial volume of the balloon is

V

1

=

5.29

L

.

To Calculate:

The final volume of the balloon.

The final moles of argon after the addition of 3.13 mol can be calculated as shown below.

n

2

=

3.13

m

o

l

+

n

1

=

3.13

m

o

l

+

2.51

m

o

l

=

5.64

m

o

l

The formula of Avogadro's law is given below.

V

1

n

1

=

V

2

n

2

.

.

.

.

.

.

(

1

)

Where,

V

1

and

V

2

are the initial and final volumes respectively.

n

1

and

n

2

are the initial and final moles respectively.

Substituting the corresponding values in equation (1), we get,

5.29

L

2.51

m

o

l

=

V

2

5.64

m

o

l

V

2

=

5.29

L

2.51

m

o

l

×

5.64

m

o

l

=

11.9

L

Hence, the volume of the balloon after the addition of extra gas is 11.9 L.